x/2x-1-(2/2x+1)=X^2+20/4X^2-1

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Solution for x/2x-1-(2/2x+1)=X^2+20/4X^2-1 equation: 


x in (-oo:+oo)

t_1 = 1-X^2-5*X^2-1-1

t_1+1/2*x^2-x = 0

t_1+1/2*x^2-x = 0

DELTA = (-1)^2-(1/2*4*t_1)

DELTA = 1-2*t_1

1-2*t_1 = 0

1-2*t_1 = 0 // - 1

-2*t_1 = -1 // : -2

t_1 = -1/(-2)

t_1 = 1/2

DELTA = 0  <=>  t_2 = 1/2

x = 1/(1/2*2) i t_1 = 1/2

x = 1 i t_1 = 1/2

( x = ((1-2*t_1)^(1/2)+1)/(1/2*2) or x = (1-(1-2*t_1)^(1/2))/(1/2*2) ) i t_1 > 1/2

( x = (1-2*t_1)^(1/2)+1 or x = 1-(1-2*t_1)^(1/2) ) i t_1 > 1/2

t_1-1/2 > 0

t_1-1/2 > 0 // + 1/2

t_1 > 1/2

x in { 1, (1-2*(1-X^2-5*X^2-1-1))^(1/2)+1, 1-(1-2*(1-X^2-5*X^2-1-1))^(1/2) }

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